A. have invited
B. invited
C. invite
D. be inviting
The Browns are ( 11) Smiths neighbors. Mr Brown's name is John. But when his neighbors talk about him,they ( 12 ) him "Mr Going-to-do . Do you know why? Mr Brown always says he is going to do something,but he ( 13) does it.Every Saturday, Mr Brown ( 14 ) to the Smiths back door and talks to Mr Smith. He always says he ( 15 ) do something."I,m going to clean my house today,"he says,( 16 ) "I'm going to wash my car tomor-row,"or"These trees in front of my house'are ( 17) big,l m going to cut them down next week."Mr Smith usually says,"( 18) ,John?"He knows his neighbor is not going to clean his house,or wash his car,or cut down any trees. Then he says,"Well,excuse me,John. I-m going to do some work in the house. "And he ( 19) .Mr and Mrs Smith often say to their only child Dick,"Are you going to do something?Then do it. Don-t be ( 20) 'Mr Going-to-do'.( )11.A.theB.a.C.oneD./
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Saul's brother left the matter entirely up to ______ and ______.A. I, heB. him, IC. me, heD. him, me
以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);
以下程序段中,循环次数不超过10的是()A.int i=10; do{ i=i+1;} while(i<0);B.int i=5; do{ i+=1;} while(i>0);C.int i=1; do{ i+=2;} while(i!=10);D.int i=6; do{ i-=2;} while(i!=1);
以下能正确计算1+2+3+…+10的程序段是 。A.i=1; s=1; do {s=s+i; i++;} while (i<10);B.do {i=1;s=0; s=s+i; i++;} while (i<=10);C.do {i=1;s=1; s=s+i; i++;} while (i<=10);D.i=1,s=0; do {s=s+i; i++;} while (i<=10);E.i=1; s=1; do {s=s+i; i++;} while (i<=10);F.i=1,s=0; do {s=s+i; i++;} while (i<10);
7、以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);
15、以下能正确计算1×2×3×4...×10的程序段是A.i=1; s=1; do { s=s*i; i++; } while(i<=10);B.do { i=1; s=1; s=s*i; i++; } while(i<=10);C.do { i=1; s=0; s=s*i; i++; } while(i<=10);D.i=1; s=0; do { s=s*i; i++; } while(i<=10);