The beef I ate at the restaurant yesterday is delicious. I'd like to have it again even if it costs().

第1题

Student: Good morning, Professor Liu. ______I'm late.Professor: You are late every morning. You were late Tuesday, yesterday...Don't you have a watch?

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第2题

3． —Come and join us，Jimmy !—I-m sorry，but I-m really busy now．lf I _______ time，l would certainly go．A． will haveB． have hadC． hadD． have

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第3题

If only we______(have)a phone! I'm tired of waiting outside the public phone box.

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第4题

-Would you like to go to the cinema?-I'd _____to go to the museum.A. ratherB. PreferC. have

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第5题

—I'd met Smith several times before.—So (have) ( ) I.

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第6题

I ____ my homework at 19:00 yesterday.A finishedB would finishC was finishingD finish

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第7题

函数ReadDat()实现从文件IN47.DAT中读取1000个十进制整数到数组xx中。请编制函数Compute()分别计算出xx中偶数的个数even、奇数的平均值avel、偶数的平均值ave2及所有偶数的方差toffc的值，最后调用函数WriteDat()把结果输出到 OUT47.DAT文件中。计算方差的公式如下：设N为偶数的个数，xx[i]为偶数，ave2为偶数的平均值。原始数据的存放格式是：每行存放10个数，并用逗号隔开(每个数均大于0且小于等于2000)。注意：部分源程序已给出。请勿改动主函数main()、读函数ReadDat()和写函数WriteDat()的内容。试题程序：include＜stdio.h＞include＜stdlib.h＞include＜string.h＞define MAX 1000int xx[MAX],odd=0,even=0;double avel=0.0,ave2=0.0,totfc=0,0void WriteDat(void);int ReadDat(void){FILE *fp;int i,j;if((fp=fopen("IN47.DAT","r"))==NULL)return 1;for(i=0;i＜100;i++){for(j=0;j＜10;j++)fscanf(fp,"%d,",&xx[i*10+j]);fscanf(fp,"/n");if(feof(fp)) break;}fclose(fp);}viod Compute(void){}void main( ){int i;for(i=0;i＜MAX;i++)xx[i]=0;if(ReadDat()){print f ( "数据文件IN47.DAT 不能打形式!\007\n");return;}Compute();printf( "EVEN=%d\nAVE1=%f\nAVE2=%f\nTOTFC=%f\n",even,avel,ave2,totfc);WriteDat();}void WriteDat(void){FILE *fp;int i;fp=fopen("OUT47.DAT","w");fprintf(fp,"%d\n%lf\n%lf\n%lf\n",even,ave1,ave2,totfc);fclose(fp);}

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